目录

案例解决SimpleDateFormat格式化时间异常-java.lang.NumberFormatException-For-input-string-20022E.20022E44

目录

案例:解决SimpleDateFormat格式化时间异常 java.lang.NumberFormatException: For input string: “20022E.20022E44”

多线程下,使用SimpleDateFormat格式化时间,会发生如下异常的情况

异常内容:

java.lang.NumberFormatException: For input string: "20022E.20022E44"
	at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:2043) ~[?:1.8.0_181]
	at sun.misc.FloatingDecimal.parseDouble(FloatingDecimal.java:110) ~[?:1.8.0_181]
	at java.lang.Double.parseDouble(Double.java:538) ~[?:1.8.0_181]
	at java.text.DigitList.getDouble(DigitList.java:169) ~[?:1.8.0_181]
	at java.text.DecimalFormat.parse(DecimalFormat.java:2089) ~[?:1.8.0_181]
	at java.text.SimpleDateFormat.subParse(SimpleDateFormat.java:1869) ~[?:1.8.0_181]
	at java.text.SimpleDateFormat.parse(SimpleDateFormat.java:1514) ~[?:1.8.0_181]
	at java.text.DateFormat.parse(DateFormat.java:364) ~[?:1.8.0_181]

解决办法比较多,我这里仅举一个案例:ThreadLocal

static String pattern ="yyyy-MM-dd";
    private static ThreadLocal<SimpleDateFormat> yyyymmdd = new ThreadLocal<SimpleDateFormat>() {
        @Override
        protected SimpleDateFormat initialValue() {
            return new SimpleDateFormat(pattern);
        }
    };

    public static String format(Date date) {
        return yyyymmdd.get().format(date);
    }

    public static Date parse(String dateStr) throws Exception {
        return yyyymmdd.get().parse(dateStr);
    }