Java异常处理1.-java.lang.ClassCastException
目录
Java异常处理—1. java.lang.ClassCastException
类型转换异常:两个类型间转换不兼容
java.lang.ClassCastException:异常解决!
下面仅仅展示部分代码:
//java1和java2都是list集合
Map map = new HashMap();
map.put("Java1",java1);
map.put("Java2",java2);
Set set = map.keySet();
for (Object obj : set){
StudentPra stu65 = (StudentPra) obj; //改行报错
System.out.println(stu65.getClassStu());
List stuList = (List) map.get(obj);
for (Object o2 : stuList){
StudentPra students = (StudentPra) o2;
System.out.println("姓名"+students.getName()+",生日"+students.getBrithday());
}
}
报错代码:
StudentPra stu65 = (StudentPra) obj;
1.首先,读报错信息:
Exception in thread “main” java.lang.ClassCastException: java.lang.String cannot be cast to cn.xiaozheng.test.StudentPra
at cn.xiaozheng.test.StudentPraTest.main(StudentPraTest.java:53)
2.剖析:
java.lang.String cannot be cast to cn.xiaozheng.test.StudentPra
类型转换异常,就是类型不兼容。
3.看代码
Map map = new HashMap();
map.put("Java1",java1);
我这里键存储的类型为String类型;
for (Object obj : set){
StudentPra stu65 = (StudentPra) obj; //改行报错
System.out.println(stu65.getClassStu());
List stuList = (List) map.get(obj);
for (Object o2 : stuList){
...
}
}
而我在改行把String类型转换为了StudentPra类型,所以在后来需要通过键名获取到键值的时候,出现类型不兼容的问题。
StudentPra stu65 = (StudentPra) obj; //改行报错
实际问题出在:
List stuList = (List) map.get(obj);
无法正确通过String类型的键获取到对应类型的值!
其实我的代码在书写的时候就有点问题:因为我定义的键的类型为String类型,所以我大可直接输出,但是现在也算是收获了一种异常处理!
正确代码:
Map map = new HashMap();
map.put("Java1",java1);
map.put("Java2",java2);
Set set = map.keySet();
for (Object obj : set){
System.out.println(obj);
List stuList = (List) map.get(obj);
for (Object o2 : stuList){
StudentPra students = (StudentPra) o2;
System.out.println("姓名"+students.getName()+",生日"+students.getBrithday());
}
}
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