leetcode日记90二叉树的锯齿形层序遍历
目录
leetcode日记(90)二叉树的锯齿形层序遍历
和上一题思路差不多,只不过有一个陷阱,就是不能用上一题的递归解法,因为逆序遍历会导致后面需要顺序的节点也逆序。
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> result;
vector<TreeNode*> tree;
vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
if(root==NULL) return result;
tree.push_back(root);
while(!tree.empty()){
int sum=tree.size();
result.push_back(vector<int> ());
for(int i=0;i<sum;i++){
if(tree[i]->left) tree.push_back(tree[i]->left);
if(tree[i]->right) tree.push_back(tree[i]->right);
}
if(result.size()%2!=1) for(int i=sum-1;i>=0;i--) result.back().push_back(tree[i]->val);
else for(int i=0;i<sum;i++) result.back().push_back(tree[i]->val);
tree.erase(tree.begin(),tree.begin()+sum);
}
return result;
}
};